11y-6+65y^2=0

Solution for 11y-6+65y^2=0 equation:

11y-6+65y^2=0

a = 65; b = 11; c = -6;
Δ = b2-4ac
Δ = 112-4·65·(-6)
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-41}{2*65}=\frac{-52}{130}
=-2/5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+41}{2*65}=\frac{30}{130}
=3/13
$